For most applicationsI ADJ could be simply ignored since it's value will be too small. LM317 Symmetrical Power Supply with Current Boost Yes. Because a) the voltage matches, and b) the amperage provided is greater than that needed, you can use a 5v-2A charger with a 5V-1A device. Is 500ma the same as 0.5 A? When I took my multimeter and took a reading on the output of the car adapter from a 5V charger, it was reading 4.14V or 3.8V, and the Nintendo 3DS charger light would blink.

Aforesaid is the process to develop an adjustable dual power supply. However, if you need the voltage to be variable in nature [for instance, 4.5V,7.5V,13V et al], simply add the VR1 in IC1-LM317 and IC2- LM337 pin. However, for this development we would like to develop a dual positive power supply, ground and negative so as to experiment it in different circuits. In regard to positive volt it is preferable to use IC LM317 [-3V,-5V,-6V,-9V,-12V,-15V at 1A] and use LM337 as the negative volt. The voltage can further be controlled by S2 [+Vout] and S3 [-Vout]. The size of the transformer is set to 2A and furthermore the IC enables holding the heat sink. The design employs a couple of identical LM317 variable regulator circuits driven through separate bridge rectifiers and AC inputs from the transformers.Sidestep all those unknowns and make sure to get exactly the right voltage from the start. Amperage Where R1 = 270 ohms as given in the diagram, R2 = the individual resistors connected with the rotary switch, and V REF= 1.25 Nevertheless, the circuit that we design here will be useful because a) The circuit has the capacity to enable positive voltage and even negative voltage [at 3 volts, 5 volts, 6 volts, 9 volts, 12 volts, 15 volts respectively keeping the output of the current under 1.5 amps; b) Uout = 1.25(1+R2/R1) + IadjR2, in which 1.25 signifies the reference voltage of the IC, and ladj indicates the current moving through the 'ADJ(ust)' pin of the device towards ground. The reference voltage is employed through control pot P1 along with various other parts with the - input pinout. The negative output voltage is well balanced with respect to the positive reference voltage using the voltage divider `see -saw' network established through the 33 k and 10 k resistors (that are bridged together through a trimming circuitry).

No, amps do not have to match, but the power supply or charger must be able to supply enough amps as required by the device being powered or charged. In practical terms, that means the amperage rating of a power supply or charger must match or exceed that required by the device it is connected to. Does more volts mean more amps? If you look closely at the small print on many power supplies, you’ll see they’re rated for anything from 100 to 250 volts. This means most can work worldwide with nothing more than an adapter to account for the physical plug differences — no voltage transformer needed. As long as the correct voltage is used, a device will draw only the amperage it needs, meaning there will not be “too many amps”. If an incorrect voltage is used — say a higher voltage than the device is rated to accept — then yes, too many amps may be drawn, and the device can be damaged. This is why it’s critical to use the correct voltage. Can I use an AC adapter with higher amps?When replacing a charger, this is easy to determine: it’ll be listed somewhere on the old charger. In your case, the old charger supplied 19 volts, so your replacement must also be 19 volts. Power supply efficiency is known as the amount of power actually provided to the internal circuitry, divided by the amount of power drawn from the mains supply. If a PSU is 50% efficient and is required to provide 50 Watts of power, 100 Watts will be drawn from the main supply. The extra 50 W is lost as heat. A 90% efficient PSU would draw 56 W in the same circumstances. What industries can power supplies be used in? A 5.6 V zener diode is employed for fixing the reference voltage. The zener value is not really crucial; if it is small, the output voltage is going to be a bit lower.